Algebra question? - xpress train 02
A train leaves Danville and northward at a speed of 75 km / h. Two hours later, leaving a train Xpress on a parallel track and travels north to 125 km / h. so far from the station are correct?
Xpress Train 02 Algebra Question?
5 comments:
D = 150 + 75T
d = 125 tonnes
125T = 150 + 75T
50t = 150
t = 3
d = 3 x 125 = 375 miles
The formula works
D = RT
where
D = distance
R = Rate
T = Time
For the first train
D1 = 75T
and the second train
D2 = 125 (T - 2)
Encounter for the two traits
D1 = D2 then
75T T = 125 (-2)
75T = 125T - 250
Reorganization
125T - 75T = 250
50T = 250
T = 5 hours
The trains will meet 5 hours after the first train left at Danville and at this stage, the trains are
D = 75 (5) = 375 miles
far from Danville.
Well, we will later on "start two hours." At this point, the slow train at 150 km. The gap closes by 50 km / h, which is necessary
150/50 = 3 hours to full fill the gap
After three hours, the train has passed 3 * 125 = 375 miles. You can check this answer by showing that the train from Danville go so far in 5 hours.
You decide when to take and then take the time to meet it by train to a train on a train at 150 km, before leaving the train, but the train goes faster, have 50 train km, up to 150 miles up to 3 hours take place (50x3 = 150) for 3 hours of train A and B will meet at 375 miles from (125x3 = 375 too)
after 3 hours. 375 miles from the station.
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